(z^2+4)(z^2-2z+1)=0

Solution for (z^2+4)(z^2-2z+1)=0 equation:

Simplifying
(z2 + 4)(z2 + -2z + 1) = 0

Reorder the terms:
(4 + z2)(z2 + -2z + 1) = 0

Reorder the terms:
(4 + z2)(1 + -2z + z2) = 0

Multiply (4 + z2) * (1 + -2z + z2)
(4(1 + -2z + z2) + z2(1 + -2z + z2)) = 0
((1 * 4 + -2z * 4 + z2 * 4) + z2(1 + -2z + z2)) = 0
((4 + -8z + 4z2) + z2(1 + -2z + z2)) = 0
(4 + -8z + 4z2 + (1 * z2 + -2z * z2 + z2 * z2)) = 0
(4 + -8z + 4z2 + (1z2 + -2z3 + z4)) = 0

Combine like terms: 4z2 + 1z2 = 5z2
(4 + -8z + 5z2 + -2z3 + z4) = 0

Solving
4 + -8z + 5z2 + -2z3 + z4 = 0

Solving for variable 'z'.

The solution to this equation could not be determined.